1) 11х^2-6x-27=8x^2-6x
11x^2-6x-27-8x^2+6x=0
3x^2-27=0
3x^2=27
x^2=27/3
x^2=9
x=3
2) 26+5y-0,5y^2=2,5y^2+26
26+5y-0,5y^2-2,5y^2-26=0
5y-3y^2=0
y(5-3y)=0
y=0 5-3y=0
3y=5
y= 5/3
3)-7x^2+13x+9=-19+13x
-7x^2 +13x +9 +19 -13x=0
-7x^2 +28 =0
7x^2=28
x^2 = 4
x=2
4) 21z+11=11+17z-5z^2
21z+11-11-17z^2=0
21z-17z^2=0
z(21-17z)=0
z=0 17z=21
я= 21/17
5)(x-5)^2+ 4x = 25
x^2-10+25 +4x =25
x^2 +4x = 10
x (x+4)=10
x=10 x+4 =10
x=6
1) 11х^2-6x-27=8x^2-6x
11x^2-6x-27-8x^2+6x=0
3x^2-27=0
3x^2=27
x^2=27/3
x^2=9
x=3
2) 26+5y-0,5y^2=2,5y^2+26
26+5y-0,5y^2-2,5y^2-26=0
5y-3y^2=0
y(5-3y)=0
y=0 5-3y=0
3y=5
y= 5/3
3)-7x^2+13x+9=-19+13x
-7x^2 +13x +9 +19 -13x=0
-7x^2 +28 =0
7x^2=28
x^2 = 4
x=2
4) 21z+11=11+17z-5z^2
21z+11-11-17z^2=0
21z-17z^2=0
z(21-17z)=0
z=0 17z=21
я= 21/17
5)(x-5)^2+ 4x = 25
x^2-10+25 +4x =25
x^2 +4x = 10
x (x+4)=10
x=10 x+4 =10
x=6
ответ 1980 на 12 школьников и 4 взрослых
на одного школьника стоимость билета 99 рублей.