Question

Вычислите: (5*(4^15)*(9^9)-4*(3^20)*(8^9))//(5*(2^9)*(6^19)-7*(2^29)*(27^6)); // - обозначение дроби. заранее большое !

Answer 1

$\frac{5*4^{15}*9^9-4*3^{20}*8^9}{5*2^9*6^{19}-7*2^{29}*{27}^6}= \frac{5*2^{30}*3^{18}-2^2*3^{20}*2^{27}}{5*2^9*2^{19}*3^{19}-7*2^{29}*{3}^{18}}= \frac{5*2^{30}*3^{18}-3^{20}*2^{29}}{5*2^{28}*3^{19}-7*2^{29}*{3}^{18}}= \\ \\ =\frac{2^{29}*3^{18}(5*2-3^2)}{2^{28}*3^{18}(5*3-7*2)}= \frac{2^{29}*3^{18}*1}{2^{28}*3^{18}*1}= 2$