Question

5x+3y=1 2x+6y=0 система урав.неравенств

Answer 1

$\left \{ {{5x+3y=1} \ | *(-2)\ \atop {2x+6y=0} \right. \\ \\ \left \{ {{-10x-6y=-2} \ \atop {2x+6y=0} \right. \\ \\ -10x+2x-6y+6y=-2+0\\ -8x=-2\\ 8x=2\\ x=\frac{2}{8}\\ \\ x=\frac{1}{4}\\ \\ 2*\frac{1}{4}+6y=0\\ 6y=-\frac{1}{2}\\ \\ y=-\frac{1}{2}*\frac{1}{6}\\ \\ y=-\frac{1}{12}$

ответ: х=1/4,  у=-1/12

Answer 2

5x+3y=1

2x+6y=0

2х=-6y

х=-3y

5*(-3y)+3y=1

-15y+3y=1

-12y=1

y=-1/12

х=-3*(-1/12)

х=1/4