Question

Разложить на множители: 1) (6m^4)n+(12m^3)n+(3m^2)n 2) a^2-2ab+b^2-y^2

Answer 1

$1)\; 6m^4n+12m^3n+3m^2n=3m^2n(2m^2+4m+1)=\\\\=6m^2n(m+1+\frac{\sqrt2}{2})(m+1-\frac{\sqrt2}{2})\\\\2)\; a^2-2ab+b^2-y^2=(a-b)^2-y^2=(a-b-y)(a-b+y)$