Question

Решить пример на дроби, возможно здесь опечатка (3/8+3/10)+(15/32-1/24)=

Answer 1

$(\frac{3}{8}+\frac{3}{10})+(\frac{15}{32}-\frac{1}{24})=1\frac{49}{480}$

1) $\frac{3}{8}+\frac{3}{10}=\frac{15+12}{40}=\frac{27}{40}$

2) $\frac{15}{32}-\frac{1}{24}=\frac{45-4}{96}=\frac{41}{96}$

3) $\frac{27}{40}+\frac{41}{96}=\frac{324+205}{480}=\frac{529}{480}=1\frac{49}{480}$

Answer 2

(3/8+3/10)+(15/32-1/24)=(3*5+3*4)/40 +(15*3-1*4)/96=27/40+41/96=(27*12+5*41)/480=529/480