Question

Сократите дробь 1) a^2+a/a^3+a^2 2) 3p+6q/p^2+2pq 3)8m-8n/9n-9m 4)3x^3+3xy^2/6yx^2+6y^3

Answer 1

$\frac{a^2+a}{a^3+a^2}=\frac{a(a+1)}{a^2(a+1)}=\frac{1}{a}\\\frac{3p+6q}{p^2+2pq}=\frac{3(p+2q)}{p(p+2q)}=\frac{3}{p}\\\frac{8m-8n}{9n-9m}=\frac{8(m-n)}{9(n-m)}=\frac{8}{9}\\\frac{3x^3+3xy^2}{6yx^2+6y^3}=\frac{3x(x^2+y^2)}{6y(x^2+y^2)}=\frac{x}{2y}$

Answer 2

1) (a^2+a)/(a^3+a^2)=a(a+1)/a²(a+1)=1/a
2) (3p+6q)/(p^2+2pq)=3(p+2q)/p(p+2q)=3/p
3)(8m-8n)/(9n-9m)=-8(n-m)/9(n-m)=-8/9
4)(3x^3+3xy^2)/(6yx^2+6y^3)=3x(x²+y²)/6y(x²+y²)=3x/6y=x/2y