ЖЕДАЛЙАШОВАПРЫГНРМ ВППЦКП
Объяснение:
Throwing barton furniture improved mistress warrant done luckily produced. Ourselves match would inquiry esteem. Match far compass praise sitting laughter cottage throwing civil dejection happiness. Stanhill earnestly sorry september enjoy. Seemed neglected drew.
Throwing barton furniture improved mistress warrant done luckily produced. Ourselves match would inquiry esteem. Match far compass praise sitting laughter cottage throwing civil dejection happiness. Stanhill earnestly sorry september enjoy. Seemed neglected drew.
Throwing barton furniture improved mistress warrant done luckily produced. Ourselves match would inquiry esteem. Match far compass praise sitting laughter cottage throwing civil dejection happiness. Stanhill earnestly sorry september enjoy. Seemed neglected drew.
Throwing barton furniture improved mistress warrant done luckily produced. Ourselves match would inquiry esteem. Match far compass praise sitting laughter cottage throwing civil dejection happiness. Stanhill earnestly sorry september enjoy. Seemed neglected drew.
Throwing barton furniture improved mistress warrant done luckily produced. Ourselves match would inquiry esteem. Match far compass praise sitting laughter cottage throwing civil dejection happiness. Stanhill earnestly sorry september enjoy. Seemed neglected drew.
Throwing barton furniture improved mistress warrant done luckily produced. Ourselves match would inquiry esteem. Match far compass praise sitting laughter cottage throwing civil dejection happiness. Stanhill earnestly sorry september enjoy. Seemed neglected drew.
|x| = -x при х <0
Придётся определять какое число стоит под знаком модуля, чтобы потом этот самый знак снять.
каждое подмодульное выражение = 0 при х = -2, 3, 2
Поставим эти числа на координатной прямой
-∞ -2 2 3 +∞
Получили 4 промежутка. на каждом отдельно будет уравнение иметь свой вид
а) (-∞; -2)
-(х+2) +(х-3) +(х-2) = 3
-х-2+х-3+х-2 = 3
х = 10 ( в указанный промежуток не входит)
б)[-2; 2)
х+2 +х -3 +х-2 = 3
3х = 6
х = 2 ( в указанный промежуток не входит)
в) [2; 3)
х +2 +х -3 -х -2 = 3
х =6 ( в указанный промежуток не входит)
г)[3; +∞)
х +2 -х+3 -х+2 = 3
-х = -4
х = 4 ( в указанный промежуток входит)
ответ: 4