Question

Решите, ! x^2-4 / (x^2-3x+2)(x+3)

Answer 1

$\frac{x^2-4}{(x^2-3x+2)(x+3)} = \frac{(x-2)(x+2)}{(x-1)(x-2)(x+3)} = \frac{x+2}{(x-1)(x+3)}$