[tex] rac{5 {}^{4} imes 49 {}^{ - 3} }{7 { }^{ - 7} imes 25 {}^{3} } [/tex] ! - id796785120221126 от AlekseyBunin007 26.11.2022 12:04

Question

Алгебра: [tex] rac{5 {}^{4} 	imes 49 {}^{ - 3} }{7 { }^{ - 7} 	imes 25 {}^{3} } [/tex] ! ​

AlekseyBunin007 · Accepted Answer

а)sin 2x=√3 cos x
2sinxcosx-√3cosx=0
cosx(2sinx-√3)=0
cosx=0⇒x=π/2+πn,n∈Z
sinx=√3/2⇒x=(-1)^n*π/3+πk,k∈Z
б)sin 2x=√2 cos x
2sinxcosx-√2cosx=0
cosx(2sinx-√2)=0
cosx=0⇒x=π/2+πn,n∈Z
sinx=√2/2⇒x=(-1)^n*π/4+πk,k∈Z в)sin(0,5п+x)+ sin 2x=0
г)cos(0,5п+x)+ sin 2x=0
-sinx+2sinxcosx=0
-sinx(1-2cosx)=0
sinx=0⇒x=πn,n∈Z
cosx=1/2⇒x=+-π/3+2πk,k∈Z
д)sin 4x+√3 sin 3x+sin 2x=0
2sin3xcosx+√3sin3x=0
sin3x(2cosx+√3)=0
sin3x=0⇒3x=πn,n∈Z⇒x=πn/3,n∈Z
cosx=-√3/2⇒x=+-5π/6+2πk,k∈Z
е)cos 3x+sin 5x=sin x
cos3x+sin5x-sinx=0
cos3x+2sin2xcos3x=0
cos3x(1+2sin2x)=0
cos3x=0⇒3x=π/2+πn,n∈Z⇒x=π/6+πn/3,n∈Z
sin2x=-1/2⇒2x=(-1)^(k+1)*π/6+πk,k∈Z⇒x=(-1)^(n+1)*π/12+πk/2,k∈Z

$\frac{5 {}^{4} \times 49 {}^{ - 3} }{7 { }^{ - 7} \times 25 {}^{3} }$
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MOGZ ответил

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MOGZ ответил

$\frac{5 {}^{4} \times 49 {}^{ - 3} }{7 { }^{ - 7} \times 25 {}^{3} }$
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