Lim(1 - cos4(x))/sin^2(4x) , если х стремиться к 0 - id841718420200112 от gjkbyf6789 12.01.2020 01:45

Question

Алгебра: Lim(1 - cos4(x))/sin^2(4x) , если х стремиться к 0

gjkbyf6789 · Accepted Answer

- 4*( - x + 7 ) = x + 17
4x - 28 = x + 17
3x = 45
x = 15

c - 32 = - 7 * ( c + 8 )
c - 32 = - 7c - 56
8c = - 24
c = - 3

3 * ( 4x - 8 ) = 3x - 6
12x - 24 = 3x - 6
9x = 18
x = 2

5 * ( x - 7 ) = 3 * ( x - 4 )
5x - 35 = 3x - 12
2x = 23
x = 11,5

4 * ( x - 3 ) - 16 = 5 * ( x - 5 )
4x - 12 - 16 = 5x - 25
4x - 28 = 5x - 25
x = - 3

8 * ( 2a - 6 ) = 2 * ( 4a + 3 )
16a - 48 = 8a + 6
8a = 54
a = 6,75

- 4 * ( 3 - 5x ) = 18x - 7
- 12 + 20x = 18x - 7
2x = 5
x = 2,5

6a + ( 3a - 2 ) = 14
6a + 3a - 2 = 14
9a = 16
a = 1 ( 7/9 )

8x - ( 7x - 142 ) = 51
8x - 7x + 142 = 51
x = - 91

Lim(1 - cos4(x))/sin^2(4x) , если х стремиться к 0

MOGZ ответил