Question

Выполните выражение 1) (а – 3)(b + 4) 4) (2x2 – x)(8x2 – 2x) 2) (x – 7)(x + 3) 5) (–a – 1)(a3 + 5) 3) (2y + 1)(5y – 6) 6) (x – 6)(x2 + 2x – 3)

Answer 1

$1).ab + 4a - 3b - 12$
$4). = (4 - x) \times (16 - 2x) = 64 - 8x - 16x + 2 {x}^{2} = 64 - 24x - 2x^{2} = 2 {x}^{2} - 24x + 64$
$2). = {x}^{2} + 3x - 7x - 21 = {x}^{2} - 4x - 21$
$5).( - a - 1)(3a + 5) = - 3 {a}^{2} - 5a - 3a - 5 = - 3 {a}^{2} - 8a - 5$
$3). = 10 {y}^{2} - 12y + 5y - 6 = 10 {y}^{2} - 7y - 6$
$6). = x ^{3} \times 2 {x}^{2} - 3x - 6 {x}^{2} - 12x + 18 = x ^{3} - 4 {x}^{2} - 15x + 18$