Question

Решите, найдите корень уравнения. -2x²-4x=0; x³-x²=0. 5z³-5z=0; z-9z³=0.

Answer 1

$-2 x^{2} -4x=0$
$-2x(x+2)=0$
$x_{1}=0$  $x_{2}=-2$

$x^{3}- x^{2} =0$
$x^{2}(x-1)=0$
$x_{1}=0$  $x_{2}=1$

$5z^{3}-5z=0$
$5z(z^{2}-1)=0$
$5z(z-1)(z+1)=0$
$z_{1}=0$  $z_{2}=1$  $z_{3} =-1$

$z-9z^{3}=0$
$z(1-9z^{2})=0$
$z(1-3z)(1+3z)=0$
$z_{1}=0$  $z_{2}= \frac{1}{3}$  $z_{3}=- \frac{1}{3}$