Решение:
π
2arccos√2/2+5arcsin(-1/2) = 2•π/4 + 5• ( - arcsin 1/2) = π/2 - 5•π/6 = 3π/6 - 5π/6 = - 2π/6 = - π/3.
ответ: - π/3.
1)
5х 10 5х 10 5х - 10 5 (х - 2)
+ = - = = = 5
х - 2 2 - х х -2 х - 2 х -2 х -2
2)
6 * √ 25 * 2 6 * 5 * √2
= = 10
√9 * 2 3 * √2
3)
6 - х 8
= -х +
4 3
6 - х -3х 8
= +
4 3 3
6 - х 8 -3х
=
4 3
p/2-5p/6= (3p-5p)/6 = -2p/6 = -p/3