1) 7cos²x+4cosx-3=0; 2) 5sin²x+cos x+5=0; 3) 4sin(x/5)= 5cos(x/5); 4) cos10x=cos8x; 5) cos3x+sin6x=0; - id925910920210327 от sagoankristina1 27.03.2021 02:16

Question

Алгебра: 1) 7cos²x+4cosx-3=0; 2) 5sin²x+cos x+5=0; 3) 4sin(x/5)= 5cos(x/5); 4) cos10x=cos8x; 5) cos3x+sin6x=0; 6) cos3x+sin3x=1.

sagoankristina1 · Accepted Answer

1)х²+3х-х-3+5 х² - 2x - 143х-х-3+5 −2−14 −2−142x+2 −2x−14 −2−142x+2 −2x−142x+2x −14−2 −2−142x+2 −2x−142x+2x −14−24x −16 −2−142x+2 −2x−142x+2x −14−24x −16x −42)2x+4.4+x −2x−2.12x+4.4+x −2x−2.13x+4.4 −2x−2.12x+4.4+x −2x−2.13x+4.4 −2x−2.13x+2x 2.1−4.42x+4.4+x −2x−2.13x+4.4 −2x−2.13x+2x 2.1−4.45x −6.52x+4.4+x −2x−2.13x+4.4 −2x−2.13x+2x 2.1−4.45x −6.5x −1.32x+4.4+x −2x−2.13x+4.4 −2x−2.13x+2x 2.1−4.45x −6.5x −1.3...

1) 7cos²x+4cosx-3=0; 2) 5sin²x+cos x+5=0; 3) 4sin(x/5)= 5cos(x/5); 4) cos10x=cos8x; 5) cos3x+sin6x=0; 6) cos3x+sin3x=1.

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