2.416.а)
(cos3x +cos5x+cos7x) / (sin3x +sin5x+ sin7x) =
(2cos5x*cos2x +cos5x) / (2sin5x*cos2x+ sin5x) =
cos5x(2cos2x + 1) / sin5x(2cos2x +1) = ctg5x .
- - - - - - - преобразование в рамках ОДЗ например cos2x ≠ -1/2
2.416.б)
4sin2ysin3y /(sin2y +sin4y - sin6y ) =
4sin2ysin3y / (2sin3y*cosy - 2sin3y*cos3y ) =
4sin2ysin3y /2sin3y(cosy - cos3y ) =2sin2y / (cosy - cos3y) =
2sin2y / (-2sin(-y)*sin2y =2sin2y / 2siny*sin2y = 1/ siny .
* * * * * * * sin2α =2sinα*cosα sin6y =sin2*(3y) = 2sin3y*cos3y 3y = α
k×12po h×8so
ответ 12kop 8 hos