Question

Номер 2.2 решить от начала до конца, надо 20
7 класс за ранее .

Answer 1

$1)2b \times ( - 3c) = (2 \times 3)(b \times c) = - 6bc \\ 2)( - 4a) \times ( - 5b) =( - 5 \times - 4)(a \times b) = \\ 20ab \\ 3)8x \times - \frac{ 1}{2} y = (8 \times - \frac{1}{2} ) (x \times y) = - 4xy \\ 4) \frac{3}{4} a \times ( - \frac{2}{3} x) = ( \frac{3}{4} \times - \frac{2}{3} )(a \times x) = \\ - \frac{1}{2} ax \\ 5) ( - 0.3m) \times ( - 5n) = \\ ( - 0.3 \times - 5)(m \times n) = 1.5mn \\ 6)( - 3a) \times 2b \times ( - c) = \\ ( - 3 \times 2 \times - 1)(a \times b \times c) = 6abc$