Question

Все ! решите последние 2 2 варианта. заранее =)

Answer 1

L =0,4Гн

С =90пФ = 9*10^-11 Ф

Т = 2pi *sqrt(LC)

$t \: = 2\pi \sqrt{lc} = \\ 6.28 \sqrt{9 \times 4 \times {10}^{ - 1} \times {10}^{ - 11} } = \\ 6.28 \times 6 \times {10}^{ - 6} = 37.8 \times {10}^{ - 6}$

2.

lambda = 2 cm= 2*10^-2 м

(lambda) = с/v

v = c / (lyambda)

$v = \frac{c}{lambda} = \frac{3 \times {10}^{8} }{2 \times {10}^{ - 2} } = 1.5 \times {10}^{10}$