x
2
+
y
2
=
16
...
...
...
...
...
...
.
.
(
1
)
x + y = 4 (2)
rearrange (2) to y = 4 - x (could do x = 4 - y )
substitute y = 4 - x into (1)
hence:
x
2
+
(
4
−
x
)
2
=
16
⇒
x
2
+
16
−
8
x
+
x
2
=
16
and
2
x
2
−
8
x
+
16
−
16
=
0
⇒
2
x
2
−
8
x
=
0
factor and solve : 2x(x - 4 ) = 0
⇒
x
=
0
,
x
=
4
substitute these values into y = 4 - x , to find corresponding values of y.
x = 0 : y = 4 - 0 = 4 → (0 , 4)
x = 4 : y = 4 - 4 = 0 → (4 , 0 )
These are the points of intersection with the line x +y = 4 and the circle
x
2
+
y
2
=
16
Answer link
Объяснение:
cd ~
mkdir folder1
cd folder1
touch file1
touch file2
touch file3
touch file4
tar cvf archive.tar *
mkdir ../folder2
cd ../folder2
touch new_file
cp ../folder1/archive.tar .
tar rvf archive.tar new_file
tar vf archive.tar --delete file3
tar vf archive.tar --list > list1
tar vf ../folder1/archive.tar --list > list2
diff list1 list2
#Разъединение выполнить не получится, потому что все файлы пустые, но если засовывать не пустые, то
split -b 10M archive.tar "part" # вместо 10M нужный размер
cat part* > joined_archive.tar
tar vf archive.tar --list
tar vf joined_archive.tar --list
tar czvf final_archive.tar archive.tar ../folder1/archive.tar joined_archive.tar
//PascalABC.NET 3.4.2
begin
var ar := arrrandom(100, -100, 100);
ar.Println.Take(5).Sum.Println;
ar.TakeLast(5).Sum.Println;
end.