def bubbleSort(arr):
n = len(arr)
count = 0
# Traverse through all array elements
for i in range(n-1):
# range(n) also work but outer loop will repeat one time more than needed.
# Last i elements are already in place
for j in range(0, n-i-1):
# traverse the array from 0 to n-i-1
# Swap if the element found is greater
# than the next element
if arr[j] > arr[j+1] :
arr[j], arr[j+1] = arr[j+1], arr[j]
count = count+1
return count
list = [8, 1, 7, 4, 3, 9, 2, 5, 6, 10]
count = bubbleSort(list)
print(count)
Объяснение:
ответ: 18
x, y: integer;
begin
//вводим x и y
readln(x);
readln(y);
//проверяем x
if (x >= 0) and (x<=20) then
writeln('X принадлежит')
else
writeln('X не принадлежит');
//проверяем y
if (y >= 0) and (y<=20) then
writeln('Y принадлежит')
else
writeln('Y не принадлежит');
end.