5)
#include <iostream>
using namespace std;
int main() {
int m;
cin >> m;
switch (m)
{
//31
case 1: case 3: case 5: case 7: case 8: case 10: case 12:
cout << 31 << endl;
break;
//30
case 4: case 6: case 9: case 11:
cout << 30 << endl;
break;
//28
case 2:
cout << 28 << endl;
break;
default:
cout << "Error!"<<endl;
break;
}
}
8)
#include <iostream>
using namespace std;
int main() {
int a, b;
cin >> a;
cin >> b;
if (a > b)
cout << a << endl << b;
else
cout << b << endl << a;
}
Объяснение:
Python 3. В задаче не даны данные для проверки, поэтому проверял на своих, вроде работает ;---)
line = input()
lst = list(line)
count = 0
for i in range(len(lst)):
if (lst[i] == ';' or lst[i] == ':') and i != len(lst):
if lst[i + 1] == '-':
while lst[i + 1] == '-':
i += 1
if lst[i + 1] == '(' or lst[i + 1] == ')' or lst[i + 1] == ']' or lst[i + 1] == '[':
if i + 2 != len(lst):
if lst[i + 2] == lst[i + 1]:
while i + 2 != len(lst) and lst[i + 2] == lst[i + 1]:
i += 1
elif lst[i + 2] == '(' or lst[i + 2] == ')' or lst[i + 2] == ']' or lst[i + 2] == '[':
continue
count += 1
print(count)
input familiya$
input imya$
print len(familiya$); "dlina familii"
print len(imya$); "dina imeni"
2
input slova1$
input slova2$
dlina1=val(slova1$)
dlina2=val(slova2$)
proizvidenie=dlina1*dlina2
print proizvidenie
3
a$="1500": b$="125"
f=len(a$)*len(b$)
print f
4
a$="super": b$="uchenik"
j$=a$+" "+b$
print j$
5
input gorod$
t$=mid$(gorod$,3,1)
print t$
6