180г - 100% NaCl + AgNO3 = NaNO3 +AgCl
х - 10% m(NaCl)=18г M(NaCl)=58.5
х=180*10=1800 M(AgCl)=143.5 m(AgCl)=x
1800/100= 18(г) x=143.5*18=2583
2583/58.5=44.15(г)
v=m/M=44.15/143.5=0.3(моль)
ответ:m(AgCl)=44.15г,v=0.3моль
180г - 100% NaCl + AgNO3 = NaNO3 +AgCl
х - 10% m(NaCl)=18г M(NaCl)=58.5
х=180*10=1800 M(AgCl)=143.5 m(AgCl)=x
1800/100= 18(г) x=143.5*18=2583
2583/58.5=44.15(г)
v=m/M=44.15/143.5=0.3(моль)
ответ:m(AgCl)=44.15г,v=0.3моль