дано
m(Zn) = 195 g
m(ZnO)-?
V(O2) - ?
2Zn+O2-->2ZnO
M(Zn) = 65 g/mol
n(Zn) = m/M = 195 / 65 = 3 mol
2n(Zn) = 2n(ZnO)
n(ZnO) = 3 mol
M(ZnO) = 81 g/mol
m(ZnO) = n*M = 3*81 = 244 g
2n(Zn) = n(O2)
n(O2) = 3*1/2 = 1.5 mol
V(O2) = n*Vm = 1,5 * 22.4 = 33.6 L
ответ 33.6 л, 244 гр
Объяснение:
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Объяснение:
2zn+o2=2zno
n(zn)=m(zn)/M(zn)=195г/65г/моль=3моль
n(zno)=n(zn)=3моль
m(zno)=3моль*81г/моль=243г
n(o2)=1/2n(zn)=3/2=1.5моль
V(o2)=n(o2)*Vm=1.5моль*22.4л/моль=33.6л