Question

Решите и объясните как переводите (если нужно) ​

Answer 1

а) $(5-3\frac{7}{16}) + (4-2\frac{9}{16}) = 1\frac{9}{16} + 1\frac{7}{16} = 3$

б) $(3-1\frac{4}{7}) + (5-2\frac{5}{7}) = 1\frac{3}{7} + 2\frac{2}{7} = 3\frac{5}{7}$

в) $(2-1\frac{5}{9}) + (4-1\frac{4}{9}) = \frac{4}{9} + 2\frac{5}{9} = 3$

г) $(2-1\frac{5}{18}) + (7-2\frac{11}{18}) = \frac{13}{18} + 4\frac{7}{18} = 4\frac{20}{18} = 5\frac{2}{18} = 5\frac{1}{9}$

а) $(6-3\frac{5}{12}) - (3-1\frac{1}{12}) = 2\frac{7}{12} - 1\frac{11}{12} = 1\frac{19}{12} - 1\frac{11}{12} = \frac{8}{12} = \frac{2}{3}$

б) $(5 - 2\frac{7}{19}) - (4-3\frac{2}{19}) = 2\frac{12}{19} - \frac{17}{19} = 1\frac{31}{19} - \frac{17}{19} = 1\frac{14}{19}$

в) $(7-3\frac{7}{11})-(4-2\frac{3}{11}) = 3\frac{4}{11} - 1\frac{8}{11} = 2\frac{15}{11} - 1\frac{8}{11} = 1\frac{7}{11}$

г) $(8-4\frac{13}{20}) - (6-5\frac{3}{20}) = 3\frac{7}{20} - \frac{17}{20} = 2\frac{27}{20} - \frac{17}{20} = 2\frac{10}{20} = 2\frac{1}{2}$

Удачи!