А 50,2 км В
> х км/ч t = 4/5 ч > 16,5 км/ч
1) 16,5 · 4/5 = 16,5 · 0,8 = 13,2 км - проедет грузовая машина за 4/5 ч;
2) 50,2 + 13,2 = 63,4 км - проедет легковой автомобиль за 4/5 ч;
3) 63,4 : 0,8 = 79,25 км/ч - скорость легкового автомобиля.
Пусть х км/ч - скорость легкового автомобиля, тогда (х - 16,5) км/ч - скорость сближения при движении вдогонку. Уравнение:
(х - 16,5) · 0,8 = 50,2
х - 16,5 = 50,2 : 8
х - 16,5 = 62,75
х = 62,75 + 16,5
х = 79,25
ответ: 79,25 км/ч.
Пошаговое объяснение:
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Тут всё понятно 44 и 44
Пошаговое объяснение: там всего 3 фигуры. одна из них треугольник, остальные две одинаковы нам известно что периметр треугольника равен 21, а одной фигур 44 а там останутся 2 одинаковые фигуры