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ghukasyangoar
ghukasyangoar
24.03.2021 14:57 •  Математика

Используя рисунок 24, a) AED b) WEF d) FEP e) FED f) DET g) AET h) REF k) DEW i) PED Найдите величину угла в градусах

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Ответ:
Yangelskiy
Yangelskiy
24.03.2021

ответ:Help translate the text from Russian into English (according to the rules as expected) without a translator.

I do not know how to get to the airport in my city, because I have never flown to other cities and countries.

I know how to get to the station (a month ago I went to my grandmother alone). If you go from my house, then you need to take a minibus 40 minutes. When the final stop is reached, you need to take bus 2 (it takes about 2 hours). This bus goes straight to the station (you just have to climb the stairs and go down to the station. There they will check bags on a special device.

to the bookstore account. We only have a library. It takes half an hour to get to the bookstore. Just take our minibus and stop near the bank. on the right side there will be a "globe" store where I always buy books

Пошаговое объяснение: Help translate the text from Russian into English (according to the rules as expected) without a translator.

I do not know how to get to the airport in my city, because I have never flown to other cities and countries.

I know how to get to the station (a month ago I went to my grandmother alone). If you go from my house, then you need to take a minibus 40 minutes. When the final stop is reached, you need to take bus 2 (it takes about 2 hours). This bus goes straight to the station (you just have to climb the stairs and go down to the station. There they will check bags on a special device.

to the bookstore account. We only have a library. It takes half an hour to get to the bookstore. Just take our minibus and stop near the bank. on the right side there will be a "globe" store where I always buy books

4,4(68 оценок)
Ответ:
Lenokin88
Lenokin88
24.03.2021

1  

Пошаговое объяснение:

1) y=(x2-5·x+8)^6

((x2-5·x+8)^6)' = (12·x-30)·(x2-5·x+8)^5

Поскольку:

((x2-5·x+8)^6)' = 6·(x2-5·x+8)^(6-1)((x2-5·x+8))' = (12·x-30)·(x2-5·x+8)^5

(x2-5·x+8)' = (x2)' + (-5·x)' + (8)' = 2·x + (-5) = 2·x-5

(x2)' = 2·x2-1(x)' = 2·x

(x)' = 1

(12·x-30)·(x2-5·x+8)^5

2) здесь не уверена

y=(sin(5·x2))^3

(sin(5·x2)^3)' = 30·x·sin(5·x2)^2·cos(5·x2)

Поскольку:

(sin(5·x2)^3)' = 3·(sin(5·x2))^(3-1)((sin(5·x2)))' = 30·x·sin(5·x2)^2·cos(5·x2)

(sin(5·x2))' = (sin(5·x2))'(5·x2)' = 10·x·cos(5·x2)

(5·x2)' = 5·2·x2-1(x)' = 10·x

(x)' = 1

30·x·sin(5·x2)^2·cos(5·x2)

При вычислении были использованы следующие правила дифференцирования:

(xa)' = axa-1

(a)' = 0

(f(g(x)))' = f(x)'*g(x)'

3) на картинке решить во жизни и смерти ">

4,6(80 оценок)
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