Question

1. Решите уравнения а) х + 1/3 = 2003
б) 255 - (y+ 155 ) = 55
3

самостоятельная работа 38б

Answer 1

1. Решить уравнения

$a)~ x + \dfrac{1}{3} =2003$

$x =2003-\dfrac{1}{3}$

$x =2002\dfrac{2}{3}$

б) 255 - (у + 155) = 55

у + 155 = 255 - 55

у + 155 = 200

у = 200 - 155

у = 45

Самостоятельная работа

2. Решить уравнения

$a)~x + \dfrac{12}{23} = \dfrac{20}{23}$

$x = \dfrac{20}{23} - \dfrac{12}{23}$

$x = \dfrac{8}{23}$

$b)~ \dfrac{28}{35} -\Big (y + \dfrac{16}{35} \Big )= \dfrac{4}{35}$

$y + \dfrac{16}{35} =\dfrac{28}{35}- \dfrac{4}{35}$

$y + \dfrac{16}{35} =\dfrac{24}{35}$

$y =\dfrac{24}{35}-\dfrac{16}{35}$

$y =\dfrac{8}{35}$

$c)~ \Big (2\dfrac{1}{12}-1\dfrac{5}{6}\Big )x = \dfrac{3}{4}$

$\Big (2\dfrac{1}{12}-1\dfrac{10}{12}\Big )x = \dfrac{3}{4}$

$\Big (1\dfrac{13}{12}-1\dfrac{10}{12}\Big )x = \dfrac{3}{4}$

$\dfrac{3}{12}x = \dfrac{3}{4}$

$\dfrac{1}{4}x = \dfrac{3}{4}$

x = 3

3. Выполнить действия

$a)~\Big (\dfrac{12}{19} + \dfrac{3}{19}\Big ) - \dfrac{9}{19} =\dfrac{6}{19}\\\\~~~~~~1)~ \dfrac{12}{19} + \dfrac{3}{19} = \dfrac{15}{19}\\\\~~~~~~2)~\dfrac{15}{19}- \dfrac{9}{19} = \dfrac{6}{19}$

$b)~\Big (\dfrac{5}{14}-\dfrac{3}{14}\Big) +\Big (\dfrac{11}{14}-\dfrac{9}{14}\Big) =\dfrac{2}{7}\\ \\~~~~~~~1)~ \dfrac{5}{14}-\dfrac{3}{14} = \dfrac{2}{14} \\\\~~~~~~~2)~\dfrac{11}{14}-\dfrac{9}{14}= \dfrac{2}{14} \\\\~~~~~~~3)~ \dfrac{2}{14}+ \dfrac{2}{14} = \dfrac{4}{14} = \dfrac{2}{7}$

4. Решить уравнение

$a)~\Big (\dfrac{6}{7}-y\Big ) + \dfrac{2}{7}=\dfrac{5}{7}$

$\dfrac{6}{7}-y =\dfrac{5}{7}- \dfrac{2}{7}$

$\dfrac{6}{7}-y =\dfrac{3}{7}$

$y =\dfrac{6}{7} - \dfrac{3}{7}$

$y = \dfrac{3}{7}$

Answer 2

1.а)

$x = 2003 - \frac{1}{3 } \\ x = \frac{6008}{3}$

б)

$255 - y - 155 = 55 \\ 100 - y = 55 \\ - y = 5 - 100 \\ - y = - 45 \\ y = 45$

3.а)

$\frac{15}{19} - \frac{9}{19} = \frac{6}{19}$

б)

$\frac{1}{7} + \frac{1}{7} = \frac{2}{7}$