Question

Решите предел lim 3x*tg(2*x)/sin^2(3x) при x=> 0

Answer 1

$\lim_{x \to 0} \frac{3x\ tg2x}{sin^23x}=\lim_{x \to 0} \frac{3x* 2x}{(3x)^2}=\lim_{x \to 0} \frac{2x}{3x}=\lim_{x \to 0} \frac{2}{3}=\frac{2}{3}$