Question

Математика (4 Задание Не нужно Делать)

Answer 1

$\displaystyle 1)\ \ 9\frac{1}{6}:\Big(4\frac{1}{3}-8\Big)+24\cdot \frac{3}{8}=\frac{55}{6}:\Big(\frac{13}{3}-8\Big)+3\cdot 3=\frac{55}{6}:\frac{-11}{3}+9=\\\\\\=-\frac{55}{6}\cdot \frac{3}{11}+9=-\frac{5}{2}+9=\frac{-5+18}{2}=\frac{13}{2}=6,5$

$2)\ \ (1,4-(-2,7)-(-1,2))\cdot (-1,2)=(1,4+2,7+1,2)\cdot (-1,2)=\\\\=-5,3\cdot 1,2=-6,36$

$3a)\ \ a=0,(8)\ \ ,\ \ \ 10a=8,(8)\\\\10a-a=8,(8)-0,(8)\\\\9a=8\ \ ,\ \ \ a=\dfrac{8}{9}\\\\\\b)\ \ a=3,5(6)\ \ ,\ \ \ 10a=35,(6)\ \ \ ,\ \ \ 100a=356,(6)\\\\100a-10a=356,(6)-35,(6)\\\\90a=321\ \ \ ,\ \ \ a=\dfrac{321}{90}=3\dfrac{51}{90}\\\\\\c)\ \ a=12\dfrac{5}{7}=\dfrac{12\cdot 7+5}{7}=\dfrac{89}{7}=12,(714285)$