Question

(2x^2+3x)+(-x+4) (y^2-5y)+(5y-2y^2) (b^2-b+7)-(b^2+b+8) (8n^3-3n^2)-(7+8n^3-2n^2) (a^2+5a+4)-(a^2+5a-4) преобразуйте в многочлен стандартного вида. надо решить это и в течении как можно меньшого срока

Answer 1

$(2 {x}^{2} + 3x) + ( - x + 4) = 2 {x}^{2} + 3x - x + 4 = 2 {x}^{2} + 2x + 4 = 2( {x}^{2} + x + 4) \\ ( {y}^{2} - 5y) + (5y - 2 {y}^{2} ) = {y}^{2} - 5y + 5y - 2 {y}^{2} = - {y}^{2} \\ ( {b}^{2} - b + 7) - ({b}^{2} + b + 8) = {b}^{2} - b + 7 - {b}^{2} - b - 8 = - 2b - 1 \\ (8 {n}^{3} - 3 {n}^{2} ) - (7 + 8{n}^{3} - 2 {n}^{2}) = 8 {n}^{3} - 3 {n}^{2} - 7 - 8{n}^{3} + 2 {n}^{2} = - {n}^{2} - 7 \\ ( {a}^{2} + 5a + 4) - ( {a}^{2} + 5a - 4) = {a}^{2} + 5a + 4 - {a}^{2} - 5a + 4 = 8$

Answer 2

(2x^2+3x)+(-x+4)=2x^2+3x-x+4=2x^2+2x

+4

(y^2-5y)+(5y-2y^2)=y^2-5y+5y-2y^2=y^2-2y^2=-y^2

(b^2-b+7)-(b^2+b+8)=b^2

-b+7-b^2-b-8=-2b-1

(8n^3-3n^2)-(7+8n^3-2n^2)=8n^3-3n^2-7-8n^3+2n^2=-n^2-7

(a^2+5a+4)-(a^2+5a-4)=a^2+5a+4-a^2-5a+4=8