Question

Модуль числа l1,7l+l-1,8l l-3,7l*l4,2l l7,6l +l-4,7l l7,4l: l2,1l l-3/7l + l-1/14l l-5/9l*l3/5l l-3,84l-l1,97l l7,5l*l4,6l l-2,9l-l-0,9l l7,2l : l-0,6l l-1 1/7l+l1 3/14l l1 1/5l*l-5/12l мне 14

Answer 1

L1,7l+l-1,8l = 1,7+1,8 = 3,5
l-3,7l*l4,2l = 3,7*4,2 = 15,54
l7,6l +l-4,7l = 7,6+4,7 = 12,3
l7,4l/l2,1l = 7,4/2,1 = 74/21 = $3 \frac{11}{21}$
l$-\frac{3}{7}$l + l$- \frac{1}{14}$l = $\frac{3}{7}+ \frac{1}{14}= \frac{6+1}{14}= \frac{7}{14}= \frac{1}{2}$
$|- \frac{5}{9}|*| \frac{3}{5} |$ = $\frac{5}{9}* \frac{3}{5}= \frac{1}{3}$ 
l-3,84l-l1,97l = 3,84-1,97 = 1,87
l7,5l*l4,6l = 7,5*4,6 = 34,5
l-2,9l-l-0,9l = 2,9-0,9 = 2
l7,2l /l-0,6l = 7,2/0,6 = 72/6 = 12
$|- \frac{11}{7} |+| \frac{13}{14} |= \frac{11}{7} +\frac{13}{14} = \frac{22}{14} +\frac{13}{14}= \frac{35}{14}=2,5$
$| \frac{11}{5} |*|- \frac{5}{12} |= \frac{11}{5} * \frac{5}{12}= \frac{11}{12}$