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nura20061
nura20061
11.03.2021 08:28 •  Математика

Прочитай рассуждение закончи решение 7020- m•3 =4080 k•6-2284=5456 n: 7+1275=6000 2160: u+4996=5000

👇
Ответ:
silverg2005p00xxj
silverg2005p00xxj
11.03.2021
7020-m•3=4080
m•3=7020-4080
m•3=2840
m=2840:3
m=980

k•6-2284=5456
k•6=5456+2284
k•6=7740
k=7740:6
k=2580

n:7+1275=6000
n:7=6000-1275
n:7=4725
n=4725:7
n=675

2160:u+4996=5000
2160:u=5000-4996
2160:u=4
u=2160:4
u=540
4,5(32 оценок)
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Ответ:
crissimakova20
crissimakova20
11.03.2021

1)On a sunny afternoon last June they were in the park.

3On a sunny afternoon last June they were in the park.

1) if i had known that you were ill last week, i`d have gone to see you. 2) tom wouldn't have entered for the examination if he had known that it would be so difficult. 3) it`s good that ann reminded me about tom`s birthday. i would have forgotten if she hadn`t reminded me. 4) i`d have sent you a post card while i was on holiday if i had had your address. 5) we might not have stayed at this hotel if george hadn't recommended it to us.

1) if i knew her number, i would telephone her. 2) i wouln't buy that coat if i were you. 3) i would give you a cigarette if i had one but i`m afraid i haven`t. 4) if you didn't go to bed so late every night, you wouldn`t be so tired all the time. 5) i wouldn`t mind living in england if the weather was better.

Пошаговое объяснение:

4,4(60 оценок)
Ответ:
tahogomelp07u2x
tahogomelp07u2x
11.03.2021

-(2+3x⁵)/x³

28x⁶-2sinx

x+5cos5x

6+3/(2(1-3x)^(3/2))

Пошаговое объяснение:

a. 1/x²-x³=d/dx(1/x²)-d/dx(x³)=-2x⁻³-3x²=-2/x³-3x²=-(2+3x⁵)/x³

b. 4x⁷+2cosx=4*(d/dx(x⁷))+2*d/dx(cosx))=4*7x⁶+2*(-d/dx(x)sinx)=28x⁶-2sinx

d/dx(cosx)=(dcosu)/du * du/dx

u=x

d/du(cosu)=-sinu

d/dx(x)=1

c. x²/2+sin5x=1/2*(d/dx(x²))+d/dx(sin(5x))=1/2*(2x)+cos(5x)*(d/dx(5x))=x+5cos5x

d/dx(sinx5x)=(dcosu)/du * du/dx

u=5x

d/du(cosu)=cosu

d. 1/√(1-3x)+6x=d/dx(1/√(1-3x))+6*d/dx(x)=6*d/dx(x)-(d/dx(1-3x)/(2(1-3x)^(3/2))=6*d/dx(x)-d/dx(1)-3*d/dx(x)*1/(2(1-3x)^(3/2))=6*d/dx(x)+3/(2(1-3x)^(3/2))=6+3/(2(1-3x)^(3/2))

d/dx(1/√(1-3x))=d/du * 1/√u * du/dx

u=1-3x

d/du(1/√u)=-1/(2u^(3/2))

4,6(93 оценок)
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