Question

Решите уравнение: 4(n+5/12)=1 целая 1/6 (6n-1 целая 1/7)

Answer 1

$4(n+ \frac{5}{12} ) = 1 \frac{1}{6} (6n-1 \frac{1}{7})$
$4n + \frac{5}{3} = \frac{7}{6} * 6n - \frac{8}{6}$
$4n + \frac{5}{3} = 7n - \frac{4}{3}$
$3n = \frac{5}{3} +\frac{4}{3}$ 
$3n = \frac{9}{3}$
$3n = 3$
$n = 1$

Answer 2

4(n+5/12)=1 1/6(6n-1 1/7)
4(n+5/12)=7/6(6n-8/7)
4n+20/12=7n-8/6
4n+5/3=7n-4/3
4n-7n=-4/3-5/3
-3n=-9/3
-3n=-3
n=-3:(-3)
n=1