Question

8*100^n/2^(2n+1)*5^(2n-2) выражение

Answer 1

$\displaystyle \frac{8\cdot 100^n}{2^{2n+1}\cdot 5^{2n-2}} = \frac{2^3\cdot (2^2\cdot5^2)^n}{2^{2n+1}\cdot 5^{2n-2}} = \frac{2^3\cdot 2^{2n}\cdot 5^{2n}}{2^{2n+1}\cdot 5^{2n-2}} = \frac{2^{3+2n}\cdot 5^{2n}}{2^{2n+1}\cdot 5^{2n-2}} \\\\=2^2\cdot 5^2=100$