Question

целых 6\7*2 целых 11\40
6)42 целых 2\3: 4 целых 20\27

Answer 1

$1)\frac{25}{49} * \frac{21}{50} = \frac{25*21}{49*50} = \frac{3}{7*2} = \frac{3}{14}$

$2)\frac{45}{64} : \frac{81}{96} = \frac{45*96}{64*81} = \frac{5*6}{4*9} = \frac{30}{36} = \frac{5}{6}$

$3)\frac{121}{140} * \frac{350}{363} = \frac{121*350}{140*363} = \frac{5}{2*3} = \frac{5}{6}$

$4)\frac{39}{203} : \frac{78}{145} = \frac{39*145}{203*78} = \frac{5}{7*2} = \frac{5}{14}$

$5)22\frac{6}{7} * 2\frac{11}{40} = \frac{160}{7} * \frac{91}{40} = \frac{160*91}{7*40} = 4*13 = 52$

$6) 42\frac{2}{3} : 4\frac{20}{27} = \frac{128}{3} : \frac{128}{27} = \frac{128*27}{3*128} = 9$

Удачи!