2tg135°+2cos225°+cig (-45)°+2sin135°

Question

Математика: 2tg135°+2cos225°+cig (-45)°+2sin135°

322fase322 · Accepted Answer

1)6-5х/3=8
6-5х = 24
- 5х = 24 - 6
-5х = 18
- х = 18 : 5
- x = 3,6
x = - 3,6

2) 2х + (¹/₃₇×1¹/₉) × (-2¹/₄) = - ³/₄
¹/₃₇×1¹/₉ = ¹/₃₇×¹⁰/₉ = ¹⁰/₃₇ₓ₉ = ¹⁰/₃₃₃
¹⁰/₃₃₃× (-2¹/₄) = ¹⁰/₃₃₃× (-⁹/₄) = - ¹⁰ˣ⁹/₃₃₃ₓ₄ = - ¹⁰/₃₇ₓ₄ = - ¹⁰/₁₄₈
тогда
2х + ( - ¹⁰/₁₄₈) = - ³/₄
2x - ¹⁰/₁₄₈ = - ³/₄
2x = - ³/₄ + ¹⁰/₁₄₈
2x = -³⁷ˣ³/₁₄₈ + ¹⁰/₁₄₈
2x = - ¹¹¹/₁₄₈ + ¹⁰/₁₄₈
2x = ⁻¹¹¹⁺¹⁰/₁₄₈
2x = - ¹⁰¹/₁₄₈
x = ( - ¹⁰¹/₁₄₈) : 2
x = ( - ¹⁰¹/₁₄₈) × ¹/₂
x = - ¹⁰¹/₁₄₈ₓ₂
x = - ¹⁰¹/₂₉₆
Проверка
2(- ¹⁰¹/₂₉₆)+ (¹/₃₇×1¹/₉) × (-2¹/₄) = - ³/₄
-²⁰²/₂₉₆ + ¹⁰/₃₃₃× (-⁹/₄) = - ³/₄
-²⁰²/₂₉₆ - ¹⁰ˣ⁹/₃₃₃ₓ₄ = - ³/₄
-²⁰²/₂₉₆ - ⁵ˣ³/₁₁₁ₓ₂ = - ³/₄
-²⁰²/₂₉₆ - ⁵/₇₄ = - ³/₄
-²⁰²/₂₉₆ - ²⁰/₂₉₆ = - ³/₄
-²⁰²⁻²⁰/₂₉₆ = - ³/₄
-²²²/₂₉₆ = - ³/₄
- ³/₄ = - ³/₄

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