y=(x^2-6x)*(x+6x-17)
y= -60
Объяснение:
Корни: (0;0) (17/7 ; 0) (6;0)
Область определения Х € R
Пересечение с осью y=(0;0)
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Пусть x^2+6x=m.
m(m-17)=-60;
m^2-17m+60=0
Sqrt(D)=sqrt(17^2-60*4)=sqrt(289-240)=7.
m1=(17+7)/2=12; m2=5
Для первого случая:
x^2+6x=12; x^2-6x-12=0;
Sqrt(D)=sqrt(36+12*4)=sqrt(9*4+12*4)=2*sqrt(21), x1,2=(-6±2*sqrt(21))/2=-3±sqrt(21)
Для второго случая:
x^2+6x=5; x^2+6x-5=0;
Sqrt(D) = sqrt (36+20)=sqrt(56)=sqrt(4*14)=2*sqrt(14)
x3,4=(-6±2sqrt(14))/2=-3±sqrt(14)
ответ: -3±sqrt(14); -3±sqrt(21)