Question

с заданием.Решить подробно.

Answer 1

$\left \{ {{2x^{2}-x=y } \atop {2x-1=y}} \right.\\\\2x^{2}-x=2x-1\\\\2x^{2}-3x+1=0\\\\D=(-3)^{2} -4*2*1=9-8=1\\\\x_{1}=\frac{3-1}{4}=\frac{1}{2}\\\\x_{2}=\frac{3+1}{4} =1\\\\\left[\begin{array}{ccc}\left \{ {{x_{1}=\frac{1}{2}} \atop {y_{1}=2*\frac{1}{2}-1}} \right. \\\left \{ {{x_{2}=1} \atop {y_{2}=2*1-1 }} \right. \end{array}\right\\\\\\\left[\begin{array}{ccc}\left \{ {{x_{1}=\frac{1}{2}} \atop {y_{1}=0 }} \right. \\\left \{ {{x_{2} =1} \atop {y_{2}=1 }} \right. \end{array}\right$

$Otvet:\boxed {(\frac{1}{2};0),(1;1)}$

Answer 2

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На фото

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