Question

Тема: решение уравнений сводящихся к квадратным. 8 класс ОЧЕНЬ

Answer 1

Объяснение:

$2( {x}^{2} + 14x + 49) + 8x + 56 - 10 = 0 \\ 2 {x}^{2} + 28x + 98 + 8x + 56 - 10 = 0 \\ 2 {x}^{2} + 36x + 144 = 0 \\ d = ( {36)}^{2} - 4 \times 2 \times 144 = 1296 - 1152 = 144 \\ x1 = \frac{ - 36 + 12}{4} = \frac{ - 24}{4} = - 6 \\ x2 = \frac{ - 36 - 12}{4} = \frac{ - 48}{4} = - 12 \\ \\ x1 = - 6 \\ x2 = - 12$

${x}^{2} - 8x + 16 + 3x - 12 - 10 = 0 \\ x ^{2} - 5x - 6 = 0 \\ d = ( {5)}^{2} - 4 \times 1 \times ( - 6) = 25 + 24 = 49 \\ x1 = \frac{5 + 7}{2} = \frac{12}{2} = 6 \\ x2 = \frac{5 - 7}{2} = - 1 \\ \\ x1 = 6 \\ x2 = - 1$

Answer 2

ответ:..................