Question

Сократите дробь : 5а^2+19а-4 1-25а^2

Answer 1

$\frac{5a^2+19a-4}{1-25a^2}=\\\\5a^2+19a-4=5(a-1/5)(a+4)\\D=441=21^2\\x_{1}=1/5, x_{2}=-4\\\\\frac{5a^2+19a-4}{1-25a^2}=\frac{5(a-1/5)(a+4)}{(1-5a)(1+5a)}=\frac{(5a-1)(a+4)}{-(5a-1)(1+5a)}=\\\\=-\frac{a+4}{1+5a}$