Question

Решите уравнение а)(х+8)^2=1 б)(х-1)^2=3

Answer 1

$1)(x+8)^2=1\\x+8=1\ ;x+8=-1\\x_1=-7\ \ \ ;x_2=-9\\\\2)(x-1)^2=3\\x-1=\sqrt3\ ;x-1=-\sqrt3\\x_1=\sqrt3+1\ ;x_2=1-\sqrt3$

Answer 2

(x+8)^2=1
x^2+16x+64=1
x^2+16x+63=0
D=k^2-ac=64-63=1
x1=-7
x2=-9