Question

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Answer 1

Объяснение:

$\frac{18}{4 {x}^{2} + 4x + 1} - \frac{1}{2 {x}^{2} - x} = \frac{6}{4 {x}^{2} - 1 } \\ \frac{18}{ {(2x + 1)}^{2} } - \frac{1}{x(2x - 1)} = \frac{6}{(2x - 1)(2x + 1)} \\ 18 \times x(2x - 1) - {(2x + 1)}^{2} = 6 \times x(2x + 1) \\ 36 {x}^{2} - 18x - 4 {x}^{2} - 4x - 1 = 12 {x}^{2} + 6x \\ 20 {x}^{2} - 28x - 1 = 0 \\ d = 784 + 80 = 864 \\ \sqrt{d} = \sqrt{864} = \sqrt{144 \times 6} = 12 \sqrt{6} \\ x1 = \frac{28 - 12 \sqrt{6} }{40} = \frac{7 - 3 \sqrt{6} }{10} \\ x2 = \frac{28 + 12 \sqrt{6} }{40} = \frac{7 + 3 \sqrt{6} }{10}$