Question

(2/3)^2*(-9)^2-(0,5)^3:(-0,05)

С решением желательно

Answer 1

Объяснение:

$( \frac{2}{3} ) {}^{2} \times ( - 9) {}^{2} - (0.5) {}^{3} \div ( - 0.05) = ( \frac{2}{3} ) {}^{2} \times 9 {}^{2} - 0.5 {}^{3} \div ( - \frac{1}{20} ) = ( \frac{2}{3} \times 9) {}^{2} + ( \frac{1}{2} ) {}^{3} \times 2 0 = (2 \times 3) {}^{2} + \frac{1}{8} \times 20 = 6 {}^{2} + \frac{1}{2} \times 5 = 36 + \frac{5}{2} = \frac{77}{2} = 38 \frac{1}{2} = 38.5$