Решить систему уравнений методом подстановки. надо) {15х-4у=8 {-3х+у=1

Question

Алгебра: Решить систему уравнений методом подстановки. надо) {15х-4у=8 {-3х+у=1

Markich7770777 · Accepted Answer

1)c3h6+hoh(н+) =c3h7oh-получение

2c3h7oh+2na=2c3h7ona+h2

ch3-ch2-ch2oh+cuo(t) =ch3-ch2-coh+cu+h2o

2)сh3-ch2-ch2-ch2oh + cuo(t) =ch3-ch2-ch2-coh +cu+h2o-получение

ch3-ch2-ch2-coh+h2=ch3-ch2-ch2-ch2oh

ch3-ch2-ch2-coh+ag2o(t) = ch3-ch2-ch2-cooh+2ag

3)2ch3-(ch2)3-cooh+2na=2ch3-(ch2)3-coona+h2

2ch3-(ch2)3-cooh+mgo=(ch3-ch2-ch2-ch2-coo)2mg+h2o

ch3-(ch2)3-cooh+naoh=ch3-(ch2)3-coona+h2o

2ch3-(ch2)3-cooh+na2co3=2ch3-(ch2)3-coona+co2+h2o

4)c2h5oh+ch3-cooh= c2h5-o-co-ch3+h2o

c5h11oh+h-cooh= c5h11-o-co-h +h2o

c7h13oh+c2h5-cooh= c7h13-o-co-c2h5+h2o

c5h11oh+ c5h11-cooh=c5h11-o-co-c5h11+ h2o