Question

2m-6 √2 решите примеры на сокращение дробей = 2 m -18 √2b+√10c = b-5c 2 n - 6m = 2 n - n√24m+6m

Answer 1

$\frac{2m-6 \sqrt{2}}{m^2-18}=\frac{2(m-3\sqrt{2})}{m^2-( \sqrt{18})^2}=\frac{2(m-3\sqrt{2})}{(m-\sqrt{18})(m+\sqrt{18})}=\frac{2(m-3\sqrt{2})}{(m-3\sqrt{2})(m+3\sqrt{2})}=\frac{2}{m+3\sqrt{2}}$
$\frac{ \sqrt{2b}+ \sqrt{10c}}{b-5c}=\frac{ \sqrt{2}(\sqrt{b}+ \sqrt{5c})}{(\sqrt{b}-\sqrt{5c})(\sqrt{b}+ \sqrt{5c})}= \frac{\sqrt{2}}{\sqrt{b}-\sqrt{5c}}$
$\frac{n^2-6m}{n^2-n \sqrt{24m}+6m}=\frac{(n-\sqrt{6m})(n+\sqrt{6m})}{n^2-2*n \sqrt{6m}+(\sqrt{6m})^2}= \frac{(n-\sqrt{6m})(n+\sqrt{6m})}{(n-\sqrt{6m})^2}= \frac{n+\sqrt{6m}}{n-\sqrt{6m}}$