Question

Решите уравнение х в квадрате -14х+33=0 и -3х в квадрате +10х-3=0

Answer 1

$x^{2} -14x+33=0$
$D= b^{2}-4ac=196-132=64= 8^{2}$
$x_{1} = \frac{-b+ \sqrt{D} }{2a} = \frac{14+8}{2}= 11$
$x_{2} = \frac{-b- \sqrt{D} }{2a}= \frac{14-8}{2}=3$
________________________________________________________
$-3x^{2}+10x-3=0$
$3 x^{2} -10x+3=0$
$D=b^{2} -4ac=100-4*3*3=64= 8^{2}$
$x_{1} = \frac{-b+ \sqrt{D} }{2a} = \frac{10+8}{6} =3$
$x_{2} = \frac{-b- \sqrt{D} }{2a} = \frac{10-8}{6}= \frac{1}{3}$

Answer 2

1) x^2- 14x + 33 =0
    D = 196-132=64
    √D=√64=8
    (14+8)/2=11; (14-8)/2=3
2) -3x^2 + 10x - 3=0
    D=100-36=64
    √D=√64=8
    (-10+8)/(-6) = 1/3 ; (-10-8)/(-6) = 3