Question

Решить неравенство: (х-1)(3-2х)> -6

Answer 1

$(x-1)(3-2x)\ \textgreater \ -6 \\ 3x-3-2x^2+2x\ \textgreater \ -6 \\ -2x^2+5x+3\ \textgreater \ 0 \\ D=b^2-4ac=49 \\ x_1_,_2= \frac{-b^+_- \sqrt{D} }{2a} \\ x_1\ \textless \ 3 \\ x_2\ \textgreater \ -0.5$