Question

1. вычислите. (125)^1/3-(64)2/3. 2.вычислите 7^-7*7^-8/7^-18. 3. выражение (32x^-10)^-3/5 3. 4. (5a^3/11)^4 4a^12/11.

Answer 1

$1)~ 125^{\frac{1}{3}}-64^{\frac{2}{3}}=(5^3)^{\frac{1}{3}}-(4^3)^{\frac{1}{3}}=5^{3\cdot \frac{1}{3}}-4^{3\cdot \frac{1}{3}}=5-4=1\\ \\ 2)~\dfrac{7^{-7}\cdot 7^{-8}}{7^{-18}}=\dfrac{7^{-7-8}}{7^{-18}}=\dfrac{7^{-15}}{7^{-18}}=7^{-15-(-18)}=7^3=343$

$3)~ (32x^{-10})^{-\frac{3}{5}}=(2^5\cdot x^{-10})^{-\frac{3}{5}}=(2^5)^{-\frac{3}{5}}\cdot (x^{-10})^{-\frac{3}{5}}=2^{-3}\cdot x^6=\dfrac{x^6}{8}$

$4)~ \left(\dfrac{5a^3}{11}\right)^4:\dfrac{4a^{12}}{11}=\dfrac{5^4\cdot a^{12}}{11^4}\cdot \dfrac{11}{4a^{12}}=\dfrac{5^4}{11^3\cdot 4}=\dfrac{625}{5324}$