4n^3*0,3n^5 а)0,12n^8 б)0,12n^15 в)1,2n^8 г)1,2n^12

Question

Алгебра: 4n^3*0,3n^5 а)0,12n^8 б)0,12n^15 в)1,2n^8 г)1,2n^12

megakrykova · Accepted Answer

F(x) = cos5x · cos(x + π/6)
g(x) = sin5x · sin(x + π/6) + 0.5√3
cos5x · cos(x + π/6) = sin5x · sin(x + π/6) + 0.5√3
cos5x · cos(x + π/6) - sin5x · sin(x + π/6) = 0.5√3
cos (6x + π/6) = 0.5√3
6x + π/6 = ⁺₋ π/6 + 2πn    n∈Z
1) 6x₁ + π/6 = + π/6 + 2πn    n∈Z 2) 6x₂ + π/6 = - π/6 + 2πn    n∈Z
1) 6x₁ = 2πn    n∈Z    2) 6x₂ = - π/3 + 2πn    n∈Z
1) x₁ = πn/3    n∈Z    2) x₂ = - π/18 + πn/3    n∈Z
ответ: x₁ = πn/3    n∈Z
x₂ = - π/18 + πn/3    n∈Z

MOGZ ответил