Question

Решить неравенства: 1) log0,25(x-1)> -2 2) log0,5(4x-3)> -2

Answer 1

1) ОДЗ:
x-1>0
x>1

$log0.25(x-1)\ \textgreater \ -2 \\ log0.25(x-1)\ \textgreater \ log0.25(0.25)^-2 \\ x-1\ \textless \ 0.25^-2 \\ x-1\ \textless \ (25/100)^-2 \\ x-1\ \textless \ (1/4)^-2 \\ x-1\ \textless \ 4^2 \\ x-1\ \textless \ 16 \\ x\ \textless \ 17$

x∈(1;17)

2) ОДЗ:
4x-3>0
x>3/4

$log0.5(4x-3)\ \textgreater \ log0.5(0.5)^-2 \\ 4x-3\ \textless \ 0.5^-2 \\ 4x-3\ \textless \ 5/10^-2 \\ 4x-3\ \textless \ 1/2^-2 \\ 4x-3\ \textless \ 2^2 \\ 4x-3\ \textless \ 4 \\ x\ \textless \ 7/4$

x∈(3/4;7/4)