Unit 4 Eating Out
Match the words in A with its explanation in B
1.a quality a) no good
2. abundant b) large quantities
3. customary c) to add to a dish to make it look
attractive
4. distinctive d) how good or bad something is
5. to garnish e) quickly
6.interior f) usual
7. inferior g) inside of building
8. relatively h) usual
9. rapidly i)comparatively
II. Complete the sentences with the above words:
1. design is the art of planning the decoration of the inside a house or an
office
4. These shoes are f good .
5. She made progess and was soon the best in the class.
6. thedi with parsley and serve!
7. We look a supply of food with us when we went hiking in the
mountains
8. He’s a good tennis player.
9. This sauce has a very taste.
Объяснение: Unit 4 Eating Out
Match the words in A with its explanation in B
1.a quality a) no good
2. abundant b) large quantities
3. customary c) to add to a dish to make it look
attractive
4. distinctive d) how good or bad something is
5. to garnish e) quickly
6.interior f) usual
7. inferior g) inside of building
8. relatively h) usual
9. rapidly i)comparatively
II. Complete the sentences with the above words:
1. design is the art of planning the decoration of the inside a house or an
office.
2. It’s to hold the door open for someone who is entering a building
behind you.
3. They were very upset. They had bought goods of quality.
4. These shoes are of good .
5. She made progress and was soon the best in the class.
6. the dish with parsley and serve!
7. We look an supply of food with us when we went hiking in the
mountains.
8. He’s a good tennis player.
9. This sauce has a very taste.
а) { y=x^2, x-y=-6;
из второго уравнения видно, что х=у-6
подставляем вместо "х" "у-6" в первое уравнение.
получаем квадратное уравнение с у-ом, решаем его, получаем корни: у=9;4, тогда
х=3;-2 (нашли из подстановки "у" в х=у-6)
б) { x+y=8, xy=12;
из первого уравнения видно, что х=8-у; подставим этот х во 2-ое уравнение, получим квадратное уравнение с "у". Решим его и получим, что корни у=6;2
найдем х, х=2;6
в) {x^2-Y^2=24, 2y-x=-7;
из 2-ого уравнения видно, что х=7+2у
подставим это во второе уравнение и получим квадратное уравнение с у, решив его, получим корни у=-1;-8(1/3).
найдем х, х=5;-9(2/3)
г) {x^2+y^2+3xy=-1, x+2y=0
из второго уравнения видно, что х=-2у, подстави это в 1-ое урав. и получим, что у^2=1; у=+-1.
тогда х=-2;2
ОДЗ: x > 0
y' = 3x² - 3/x = (3x³ -3)/х
(3x³ -3)/х = 0
(3x³ -3) = 0, ⇒ 3х³ = 3, ⇒ х³ = 1, ⇒ х = 1
х ≠ 0
(0) - (1) + +∞ знаки производной
убывает возрастает